Archimedes's Principle

Archimedes's Principle

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Physics Class: 210

Lab section: B

Date Performed: 3-13-02

Date Submitted: 3-20-02

Lab Partner:

Sample Calculations

1. Weight = mass x 9.80 g/cm^3

W= 45g x 9.80 N

W= 44,100 dynes

2. Buoyant force (calculated) = weight in air Ð'- weight in water

BF = 44,100 dynes Ð'- 38710 dynes

BF = 5390 dynes

3. Volume of Water = radius^2 x length

V= (.63cm) (4.65cm)

V= 5.80 cm

4. Buoyant force (measured) = mass in air/ density

BF= (44,100 g) / (7.76 g/cm^3)

BF= 5684 cm^3

5. % difference = BF calculated Ð'- BF measured/ BF measured

% difference = 5390 Ð'- 5684 / 5684

% difference = 5.4 %

6. Density = Mass / Volume

Density = 45 g / 5.80 cm^3

Density = 7.76 g/cm^3

7. Volume of wood = length x width x height

V = (7.62cm) (7.63cm) (3.86 cm)

V = 224. 42 cm^3

Questions

2.) Because an overweight person displaces more fluid when stepping into a pool. By displacing more fluid, the person creates a greater buoyant force making it easier for him to swim.

5.c) By placing a battery into the water with a floating rod into its deep cylindrical cavity it is quite easy to determine the condition of the battery. The diluted battery will have a much higher density than that of a highly charged battery. From the observation of how the battery floats you can tell its condition.

8.) We were able to find the volume of displace water in Part II quite easily. First we placed a large tupperware container on the table