Enthalpy Change of Cumbustion of Calcium Carbonates
Essay by review • March 8, 2011 • Research Paper • 674 Words (3 Pages) • 1,740 Views
Plan
Equipment
пÑ"ј 2.54g of Caco3
пÑ"ј 2.53g of Cao
пÑ"ј 2.0 mol dm-3 hydrochloric acid
пÑ"ј Scale
пÑ"ј 50cm3 measuring cylinder
пÑ"ј Thermometer
пÑ"ј Polystyrene cup
пÑ"ј Weighing bottle
Method
I. I will weigh a weighing bottle containing 2.53g of calcium carbonate
II. Using a measuring cylinder of 50cm3 I will measure 50cm3 of 2mol dm-3 of hydrochloric acid then pour it into a polystyrene cup
III. I will measure the initial temperature of the acid using a measuring cylinder, and then I will add the calcium carbonate to the acid. I will carefully stir the mixture in the cup with the thermometer and then take the final temperature reading when the reaction is complete.
IV. The weigh the weighing bottle again.
V. Repeat this instruction using Calcium Oxide. Record data on appropriate table
Risk assessment
Hazard Nature of Hazard Precaution
Calcium oxide corrosive Be careful when adding CaO into HCl acid, avoid skin contact.
Wear safety goggles.
Hydrochloric acid irritant Be careful when measuring the volume of acid required for the reactions . Wear safety goggles
Analysis
Mass of calcium carbonate + weighing bottle 14.37g
Mass of empty weighing bottle 11.84g
Mass of calcium carbonate used 2.53g
Initial temperature of the acid 22oC
Temperature of the solution when the reaction is complete 26 oC
Temperature change of the reaction 4 oC
Mass of calcium oxide + weighing bottle 13.44g
Mass of empty weighing bottle 10.90g
Mass of calcium oxide used 2.54g
Initial temperature of the acid 23 oC
Temperature of the solution when the reaction is complete 40 oC
Temperature change during the reaction 17 oC
To calculate the energy change of the reaction between calcium carbonate and hydrochloric acid I will assume that HCl has the same density 1gcm-3 and same specific heat capacity as water- 4.2g-1k-1.
The volume of hydrochloric acid used in this reaction is 50cm3 but I will assume that as a mass it is 50g. Using the formula E = MCв?†T, I can then calculate the energy change of the reaction.
E = 50 Ð"-- 4.2 Ð"-- 4
= 840j
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